Integrand size = 16, antiderivative size = 44 \[ \int \frac {1}{\sqrt {3+4 x^2-2 x^4}} \, dx=\frac {\operatorname {EllipticF}\left (\arcsin \left (\sqrt {\frac {2}{2+\sqrt {10}}} x\right ),\frac {1}{3} \left (-7-2 \sqrt {10}\right )\right )}{\sqrt {-2+\sqrt {10}}} \]
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Time = 0.05 (sec) , antiderivative size = 44, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.125, Rules used = {1109, 430} \[ \int \frac {1}{\sqrt {3+4 x^2-2 x^4}} \, dx=\frac {\operatorname {EllipticF}\left (\arcsin \left (\sqrt {\frac {2}{2+\sqrt {10}}} x\right ),\frac {1}{3} \left (-7-2 \sqrt {10}\right )\right )}{\sqrt {\sqrt {10}-2}} \]
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Rule 430
Rule 1109
Rubi steps \begin{align*} \text {integral}& = \left (2 \sqrt {2}\right ) \int \frac {1}{\sqrt {4+2 \sqrt {10}-4 x^2} \sqrt {-4+2 \sqrt {10}+4 x^2}} \, dx \\ & = \frac {F\left (\sin ^{-1}\left (\sqrt {\frac {2}{2+\sqrt {10}}} x\right )|\frac {1}{3} \left (-7-2 \sqrt {10}\right )\right )}{\sqrt {-2+\sqrt {10}}} \\ \end{align*}
Result contains complex when optimal does not.
Time = 10.04 (sec) , antiderivative size = 51, normalized size of antiderivative = 1.16 \[ \int \frac {1}{\sqrt {3+4 x^2-2 x^4}} \, dx=-\frac {i \operatorname {EllipticF}\left (i \text {arcsinh}\left (\sqrt {\frac {2}{-2+\sqrt {10}}} x\right ),-\frac {7}{3}+\frac {2 \sqrt {10}}{3}\right )}{\sqrt {2+\sqrt {10}}} \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 83 vs. \(2 (34 ) = 68\).
Time = 0.32 (sec) , antiderivative size = 84, normalized size of antiderivative = 1.91
method | result | size |
default | \(\frac {3 \sqrt {1-\left (-\frac {2}{3}+\frac {\sqrt {10}}{3}\right ) x^{2}}\, \sqrt {1-\left (-\frac {2}{3}-\frac {\sqrt {10}}{3}\right ) x^{2}}\, F\left (\frac {x \sqrt {-6+3 \sqrt {10}}}{3}, \frac {i \sqrt {6}}{3}+\frac {i \sqrt {15}}{3}\right )}{\sqrt {-6+3 \sqrt {10}}\, \sqrt {-2 x^{4}+4 x^{2}+3}}\) | \(84\) |
elliptic | \(\frac {3 \sqrt {1-\left (-\frac {2}{3}+\frac {\sqrt {10}}{3}\right ) x^{2}}\, \sqrt {1-\left (-\frac {2}{3}-\frac {\sqrt {10}}{3}\right ) x^{2}}\, F\left (\frac {x \sqrt {-6+3 \sqrt {10}}}{3}, \frac {i \sqrt {6}}{3}+\frac {i \sqrt {15}}{3}\right )}{\sqrt {-6+3 \sqrt {10}}\, \sqrt {-2 x^{4}+4 x^{2}+3}}\) | \(84\) |
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none
Time = 0.08 (sec) , antiderivative size = 36, normalized size of antiderivative = 0.82 \[ \int \frac {1}{\sqrt {3+4 x^2-2 x^4}} \, dx=\frac {1}{6} \, {\left (\sqrt {10} + 2\right )} \sqrt {\sqrt {10} - 2} F(\arcsin \left (\frac {1}{3} \, \sqrt {3} x \sqrt {\sqrt {10} - 2}\right )\,|\,-\frac {2}{3} \, \sqrt {10} - \frac {7}{3}) \]
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\[ \int \frac {1}{\sqrt {3+4 x^2-2 x^4}} \, dx=\int \frac {1}{\sqrt {- 2 x^{4} + 4 x^{2} + 3}}\, dx \]
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\[ \int \frac {1}{\sqrt {3+4 x^2-2 x^4}} \, dx=\int { \frac {1}{\sqrt {-2 \, x^{4} + 4 \, x^{2} + 3}} \,d x } \]
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\[ \int \frac {1}{\sqrt {3+4 x^2-2 x^4}} \, dx=\int { \frac {1}{\sqrt {-2 \, x^{4} + 4 \, x^{2} + 3}} \,d x } \]
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Timed out. \[ \int \frac {1}{\sqrt {3+4 x^2-2 x^4}} \, dx=\int \frac {1}{\sqrt {-2\,x^4+4\,x^2+3}} \,d x \]
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